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8x^2+35x=-12
We move all terms to the left:
8x^2+35x-(-12)=0
We add all the numbers together, and all the variables
8x^2+35x+12=0
a = 8; b = 35; c = +12;
Δ = b2-4ac
Δ = 352-4·8·12
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-29}{2*8}=\frac{-64}{16} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+29}{2*8}=\frac{-6}{16} =-3/8 $
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